Fix S3 upload error: Pass file_id as keyword argument in Celery tasks
Co-authored-by: christianlouis <361235+christianlouis@users.noreply.github.com>
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@@ -157,7 +157,7 @@ def embed_metadata_into_pdf(self, local_file_path: str, extracted_text: str, met
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# Trigger the next step: final storage.
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logger.info(f"[{task_id}] Queueing final storage task")
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log_task_progress(task_id, "embed_metadata_into_pdf", "success", "Metadata embedded, queuing finalization", file_id=file_id)
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finalize_document_storage.delay(original_file, final_file_path, metadata, file_id)
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finalize_document_storage.delay(original_file, final_file_path, metadata, file_id=file_id)
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# After triggering final storage, delete the original file if it is in workdir/tmp.
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workdir_tmp = os.path.join(settings.workdir, TMP_SUBDIR)
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@@ -228,7 +228,7 @@ def send_to_all_destinations(self, file_path: str, use_validator=True, file_id:
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logger.info(f"[{task_id}] Queueing {file_path} for {service_name} upload")
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log_task_progress(task_id, f"queue_{service_name}", "in_progress", f"Queueing upload to {service_name}", file_id=file_id)
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try:
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task = service["upload_func"].delay(file_path, file_id)
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task = service["upload_func"].delay(file_path, file_id=file_id)
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results[f"{service_name}_task_id"] = task.id
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queued_count += 1
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log_task_progress(task_id, f"queue_{service_name}", "success", f"Queued for {service_name}", file_id=file_id)
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