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Fix S3 upload error: Pass file_id as keyword argument in Celery tasks

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Co-authored-by: christianlouis <361235+christianlouis@users.noreply.github.com>
This commit is contained in:
copilot-swe-agent[bot]
2026-02-07 21:56:38 +00:00
parent 863c820265
commit 90d69979dc
3 changed files with 69 additions and 3 deletions
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app/tasks/send_to_all.py
+1 -1
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@@ -228,7 +228,7 @@ def send_to_all_destinations(self, file_path: str, use_validator=True, file_id:
logger.info(f"[{task_id}] Queueing {file_path} for {service_name} upload")
log_task_progress(task_id, f"queue_{service_name}", "in_progress", f"Queueing upload to {service_name}", file_id=file_id)
try:
task = service["upload_func"].delay(file_path, file_id)
task = service["upload_func"].delay(file_path, file_id=file_id)
results[f"{service_name}_task_id"] = task.id
queued_count += 1
log_task_progress(task_id, f"queue_{service_name}", "success", f"Queued for {service_name}", file_id=file_id)